z^(1/2)-7z^(1/4)+10=0

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Solution for z^(1/2)-7z^(1/4)+10=0 equation: 


D( z )

z < 0

z < 0

z in <0:+oo)

z^(1/2)-(7*z^(1/4))+10 = 0

z^(1/2)-7*z^(1/4)+10 = 0

t_1 = z^(1/4)

1*t_1^2-7*t_1^1+10 = 0

t_1^2-7*t_1+10 = 0

DELTA = (-7)^2-(1*4*10)

DELTA = 9

DELTA > 0

t_1 = (9^(1/2)+7)/(1*2) or t_1 = (7-9^(1/2))/(1*2)

t_1 = 5 or t_1 = 2

t_1 = 2

z^(1/4)-2 = 0

1*z^(1/4) = 2 // : 1

z^(1/4) = 2

z^(1/4) = 2 // ^ 4

z = 16

t_1 = 5

z^(1/4)-5 = 0

1*z^(1/4) = 5 // : 1

z^(1/4) = 5

z^(1/4) = 5 // ^ 4

z = 625

z in { 16, 625 }

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